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AP Math 11 Online
OpenStudy (preetha):

A graphing calculator is required for these problems. 1. The temperature of water in a tub at time t is modeled by a strictly increasing, twice-differentiable function W, where Wt is measured in degrees Fahrenheit and t is measured in minutes. At time t 0, the temperature of the water is 55F. The water is heated for 30 minutes, beginning at time t 0. Values of Wt at selected times t for the first 20 minutes are given in the table above. (a) Use the data in the table to estimate \(\large W'(12)\). Show the computations that lead to your answer.

OpenStudy (preetha):

Wait, let me post the table.

OpenStudy (preetha):

t (minutes) 0 4 9 15 20 Wt (degrees Fahrenheit) 55.0 57.1 61.8 67.9 71.0

OpenStudy (dbzfan836):

@Broskishelleh may be able to help, or @satellite73 would be better for assistance

OpenStudy (dbzfan836):

@Preetha

OpenStudy (aum):

You can use a regression calculator to fit a quadratic function (least square fit) and then find w(12).

OpenStudy (anonymous):

looks kind of linear we can make an equation would help if we know if it was polynomial or exponential http://www.wolframalpha.com/input/?i=%280%2C55%29%2C%284%2C57.1%29%2C%289%2C61.8%29%2C%2815%2C67.9%29%2C%2820%2C71%29

OpenStudy (dbzfan836):

Alright, anybody here that does not know the answer, please leave to help others. it is unfair for alot of people to be at a question that needs an answer/explanation

OpenStudy (anonymous):

here is the polynomial i would ignore the first term http://www.wolframalpha.com/input/?i=polynomial+%280%2C55%29%2C%284%2C57.1%29%2C%289%2C61.8%29%2C%2815%2C67.9%29%2C%2820%2C71%29

OpenStudy (broskishelleh):

I know now what to do: w(12) = w(15) - w(9)/ 15 - 9 = 67.9 - 61.8/ 6

OpenStudy (anonymous):

says to use a graphing calculator, so i imagine wolfram is the way to go

OpenStudy (xapproachesinfinity):

how many medals will i get if i answered lol

OpenStudy (broskishelleh):

This would make the answer 1.017 degrees Fahrenheit increasing a minute approximately

OpenStudy (aum):

Given 5 points, a fourth degree polynomial will be an EXACT fit for the given data.

OpenStudy (anonymous):

@Broskishelleh with that method you would make the answer \[61.8+1.017\]

OpenStudy (broskishelleh):

Ah, correct I am sorry for my forgetfullness

OpenStudy (broskishelleh):

Was I correct @satellite73

OpenStudy (anonymous):

sure why not? it says estimate, and it says the function is increasing so split the difference

OpenStudy (broskishelleh):

I can't believe I am right, I just answered the owners question...WHAT A GREAT HONOR!

OpenStudy (broskishelleh):

@Preetha Was it a good answer?

OpenStudy (camerondoherty):

Preetha is Just looking around Aka: Offline Lol But good Job c:

OpenStudy (preetha):

Naah. I am here. Thanks for that awesome discussion. Hope to see many more of these discussions this year!

OpenStudy (zarkon):

this data is highly correlated to a quadratic function. Do a quadratic regression and find the derivative of the best fit quadratic evaluated at 12

OpenStudy (broskishelleh):

@Preetha Can I message you? I have some questions...

OpenStudy (anonymous):

Im sure she will

OpenStudy (preetha):

Yes, you can certainly message me!

OpenStudy (preetha):

Thanks everyone again.

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