Question

calcute the value of [-OH] from the given [H3O+] in each solution and label the solution as acidic or basic

A) [H3O+]=10^-3 M;

B) [H30+]=10^-9 M.

Answer 1

@Somy

Answer 2

i gtg

Answer 3

this is full question?

Answer 4

yes

Answer 5

@Kainui sweetheart :* help this kid plz i need to leave :3

Answer 6

see if you can help me

Answer 7

it so easy

Answer 8

is that all of the question? what solution?
Chemistry was fun but I really don't remember much, sorry

Answer 9

we know that
[H3O+] * [OH-] = \[10^{-14}\]
and also PH = 14 - POH
or PH= -Log (H3O+) and POH = -Log (OH-)
us i know .......... welcome

Answer 10

OK so i dont see how you get the solution

Answer 11

i dont get it

Answer 12

@joannablackwelder will you please help

Answer 13

@preetha will you be able to help?

Answer 14

for the solution A is an acide PH= 3 <7
and B is basic PH= 9 > 7

Answer 15

@Tech1 will you please help? your knowledge is more recent? I have forgotten a lot of this.

Answer 16

for the place where we put the answer is

A) _____*10___M

WHAT DO I FILL THESE WITH BY

Answer 17

For the solution A we have : [H3O+]=10^-3 M; ====> Ph = 3 =====> POH = 14-3 = 11 =====> \[[OH-] = 10^{-11}\] ======> there are a little of OH- in A so is an Acid solution

Answer 18

For Solution B we have : [H30+]=10^-9 M ===> PH=9 ===> POH = 14-9 = 5 ====>\[[OH−]=10^{-5}\] ====so====> in B there are some of OH- so its a basic solution

Answer 19

is it 1.00*10^-11

Answer 20

and B

Answer 21

same

Answer 22

1.0

Answer 23

\[1*10^{-5}\]

Answer 24

THANKS

Answer 25

welcome .....(who?)

Answer 26

CAN YOU HELP WITH ONE MORE