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Mathematics 16 Online
OpenStudy (anonymous):

(sinx+cosx)(cscx+secx)

OpenStudy (anonymous):

You still can't get at it?

OpenStudy (anonymous):

i originally got 1/cosxsinx

OpenStudy (anonymous):

or 1

OpenStudy (anonymous):

how ever did you get it? show your your work.

OpenStudy (anonymous):

\[(\sin x+cosx)(cscx+secx) =(sinx+cosx)(1/sinx+1/cosx) = \sin^2+\cos^2/cosxsinx=1/cosxsinx\]

OpenStudy (anonymous):

i ended up with 1

OpenStudy (anonymous):

I can't see the answer but is should be 2 + 1/sinxcosx.

OpenStudy (anonymous):

*it

OpenStudy (anonymous):

let me show my work..

OpenStudy (anonymous):

ok yeah because thats not one of my answer choices. and im confused

OpenStudy (anonymous):

|dw:1409746303011:dw|

OpenStudy (anonymous):

ok i see it is one of my answer choices. I just did it incorrectly thanks so much

OpenStudy (anonymous):

No problem!

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