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(sinx+cosx)(cscx+secx)
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You still can't get at it?
i originally got 1/cosxsinx
or 1
how ever did you get it? show your your work.
\[(\sin x+cosx)(cscx+secx) =(sinx+cosx)(1/sinx+1/cosx) = \sin^2+\cos^2/cosxsinx=1/cosxsinx\]
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i ended up with 1
I can't see the answer but is should be 2 + 1/sinxcosx.
*it
let me show my work..
ok yeah because thats not one of my answer choices. and im confused
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|dw:1409746303011:dw|
ok i see it is one of my answer choices. I just did it incorrectly thanks so much
No problem!
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