Chemistry
7 Online
OpenStudy (toxicsugar22):
calculate the value of [H30+] from the give [-OH] and label the solution as acidic or basic
A. 2.00*10^-3 M
B. 9.59*10^-9
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
[H3O+][OH-]=1x10^-14
OpenStudy (joannablackwelder):
Can you calculate [H3O+] for A?
OpenStudy (toxicsugar22):
walk me through the steps
OpenStudy (toxicsugar22):
how do i do that
OpenStudy (joannablackwelder):
Substitute the value for OH- and solve for H3O+
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
You can do it! :)
OpenStudy (toxicsugar22):
nope i tried
OpenStudy (joannablackwelder):
What did you try?
OpenStudy (toxicsugar22):
on my own i dont see a way
OpenStudy (toxicsugar22):
i tried doing -log(2.00*10^-3 M)
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Why are you using that equation?
OpenStudy (joannablackwelder):
That would solve for pOH, but we aren't looking for that now.
OpenStudy (joannablackwelder):
Use the equation I gave you.
OpenStudy (toxicsugar22):
1x10^-14
OpenStudy (toxicsugar22):
i dont know help me and ill folow along
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (toxicsugar22):
please
OpenStudy (joannablackwelder):
[H3O+][OH-] = 1x10^-14
Can you substitute the value for [OH-] given?
OpenStudy (toxicsugar22):
im slowly saying no becuae I dont really know
OpenStudy (joannablackwelder):
Ok. I will show you.
[H3O+][2x10^-3] = 1x10^-14
OpenStudy (joannablackwelder):
Do you see how I did that?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (toxicsugar22):
yes
OpenStudy (joannablackwelder):
Ok, good. :) Now, can you solve for [H3O+]?
OpenStudy (toxicsugar22):
dont let me do this bymyself please. I am pullingmy hair out just foing this problem
im not really savvy in chemistry
OpenStudy (joannablackwelder):
I am helping you. This part is the algebra you did in the last problem. You can do it!
OpenStudy (joannablackwelder):
Think of it like this:
(2x10^-3)x=1x10^-14
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Solve for x.
OpenStudy (toxicsugar22):
it it x=1/20000000
OpenStudy (joannablackwelder):
Close. I get 1/200000000000 or 5x10^-12
OpenStudy (toxicsugar22):
so 5x10^-12is the anwer for A
OpenStudy (toxicsugar22):
SOLUTION
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
(1x10^-14)/(2x10^-3)
OpenStudy (joannablackwelder):
Right.
OpenStudy (joannablackwelder):
That is the first part for A.
OpenStudy (joannablackwelder):
We still need to find whether the solution is acid or basic though.
OpenStudy (joannablackwelder):
This you can get using the equation you mentioned before but with [H3O+].
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
pH=-log[H3O+]
and pH of less than 7 is acidic, greater than 7 is basic
OpenStudy (toxicsugar22):
i i meant basic as it is greater than 7
OpenStudy (joannablackwelder):
Yes! I get pH =11.3 which is basic :)
OpenStudy (toxicsugar22):
now we have to do part b
OpenStudy (joannablackwelder):
Ok.It is the same exact procedure. Can you try?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (toxicsugar22):
[H3O+][ 9.59*10^-9] = 1x10^-14
OpenStudy (toxicsugar22):
is it
OpenStudy (joannablackwelder):
Godd!
OpenStudy (joannablackwelder):
*good haha
OpenStudy (toxicsugar22):
(9.59*10^-9)x = 1x10^-14
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Yup
OpenStudy (toxicsugar22):
x=1.04275*10^-6
OpenStudy (joannablackwelder):
Me too!
OpenStudy (toxicsugar22):
and it is acidic
OpenStudy (toxicsugar22):
so it is 1.04*10^-6
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (toxicsugar22):
right
OpenStudy (joannablackwelder):
Right! You did it! :)
OpenStudy (toxicsugar22):
and it is acid
OpenStudy (joannablackwelder):
Correct.
OpenStudy (toxicsugar22):
and it 1.04*10^-6 to three sig figs like 1.04 or is it just 1
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
1.04 is 3 sig figs
OpenStudy (toxicsugar22):
(2.33*10^-10)x=1x10^-14
OpenStudy (toxicsugar22):
can you help me solve that
OpenStudy (toxicsugar22):
i got 0.0000429185
OpenStudy (toxicsugar22):
right
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Yup!
OpenStudy (joannablackwelder):
Or 4.29x10^-5
OpenStudy (toxicsugar22):
and it is acidic
OpenStudy (joannablackwelder):
Is the 2.33x10^-10 the [H3O+]?
OpenStudy (joannablackwelder):
or [OH-]?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
pH=-log[H3O+]
OpenStudy (toxicsugar22):
NO SRRY IT IS OH-
OpenStudy (joannablackwelder):
Then yup :)
OpenStudy (toxicsugar22):
i meant acidic
OpenStudy (toxicsugar22):
rigt
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (joannablackwelder):
Yes, acidic