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Calculus1
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Find the derivative of f(x)=secx/sqrt(2tanx)
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\[f(x)=\frac{\sec(x)}{\sqrt{2\tan(x)}}\]
yess that's the equation
good lord your math teacher must hate you i cannot see a simple way to do this you are going to have to use the quotient rule and a raft of algebra
ahhahha well, the answer is supposed to be \[-\sqrt{2}secx/2\tan ^{2}x\]
\[\left(\frac{f}{g}\right)'=\frac{gf'-fg'}{g^2}\] with \[f(x)=\sec(x), f'(x)=\sec(x)\tan(x)\] \[g(x)=\sqrt{2\tan(x)},g'(x)=\frac{\sec^2(x)}{\sqrt{2\tan(x)}}\]
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maybe the algebra will work, who knows?
I tried it like that previously and my answer is still off
i can't do it wolfram gives a different answer but probably uses some trig identity
ohh okkk thanks anyway! :)
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