does anyone know calc AB?
evaluate: lim as x approaches 2 4/radical 18-x -1 divided by x-2/radical 18-x

Question

does anyone know calc AB?
evaluate: lim as x approaches 2  4/radical 18-x -1 divided by x-2/radical 18-x

anonymous · Answer

@loser66 please help!!!! youre my only option test tomorrow

loser66 · Answer

can you use the draw box to draw it out? or use latex ?? It is unclear to me

anonymous · Answer

https://docs.google.com/viewer?a=v&pid=sites&srcid=ZGVmYXVsdGRvbWFpbnxtYmFybmVzbWF0aHxneDozMjBiMGIyMGEwZGMwYzc @Loser66 number 22 in case I wrote it weird

anonymous · Answer

know it, yes, 
read it, no

anonymous · Answer

@satellite73 @Loser66 I posted a link to the review question im asking

loser66 · Answer

Let satelite73 help. :)

anonymous · Answer

bunch of algebra, eliminate the compound fraction
you might want to start by multplying top and bottom by $\sqrt{18-x}$

anonymous · Answer

done

anonymous · Answer

$$\frac{4-\sqrt{18-x}}{x-2}$$ maybe?

loser66 · Answer

yup, then l'hopital rule

anonymous · Answer

I think that's it

anonymous · Answer

then rationalize the numerator by multiplying top and bottom by $4+\sqrt{18-x}$

anonymous · Answer

yes I remember now!!!! thanks sooo sooo much

anonymous · Answer

no need for l'hopital and besides you didn't get there yet

anonymous · Answer

ok. so I got 16- radical18-x over (x-2)(4+rad18-x)

loser66 · Answer

why not?@satellite73  still get the form 0/0

anonymous · Answer

sorry the radicals cancel out on the top foregot

anonymous · Answer

@loser can you help me he left?

anonymous · Answer

$$(-x-2)\div(x-2)(4+\sqrt{18-x}$$

anonymous · Answer

@loser66 shouldn't (-x-2) be (x-2)

anonymous · Answer

that's wrong. The correct answer is 1/8 I have all fo the answers just no work. The way I did it was correct I just got -x-2 instead of x-2 so those two would cancel out. Once those two cancel out you plug two into the equation and get 1/8 :)

anonymous · Answer

Im in ab all this chapter is about ar elimits derivitives are next chapter.

anonymous · Answer

correct

anonymous · Answer

K

loser66 · Answer

ok, so take his way, :)

loser66 · Answer

$$lim_{x\rightarrow 2}\dfrac{(4-\sqrt{18-x})(4+\sqrt{18-x})}{(x-2)(4+\sqrt{18-x})}$$

anonymous · Answer

yup did that but im getting -x-2 instead of x-2 do you see where I am going wrong?

loser66 · Answer

numerator: = 4^2 -(18-x) = 16-18+x= x-2

anonymous · Answer

thanks! can you help me with another?

loser66 · Answer

cancel out with the denominator, you just have 
$$lim_{x\rightarrow 2}\dfrac{1}{(4+\sqrt{18-x})}=1/8$$

loser66 · Answer

you do, I check

anonymous · Answer

ok. ill start a new topic. im gong to do number 10