Question

prove that the sum of two sides of a triangle is greater than twice the median bisecting the third side

Answer 1

@ganeshie8 this is a nice proof , wanna try ?

Answer 2

we could use the triangle inequality theorem (assuming this is not what they want to be proven)

Answer 3

i should make some scale lol

Answer 4

this is better hehe

Answer 5

since diagonal AE and BC bisect each other then ABEC is parallelogram.

PS :- AD=DE by constract assumtion , CD=DB since AD is meadian thus D is the midpoint of CB

Answer 6

as i said ABEC is parallelogram ( by SAS stuff or simply you say diagonal AE and BC bisect each)