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two electrical charges 200 muC and 400 muC are placed 5 metres apart in a vacuum. Calculate the electrostatic force between them.
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muC is simply \(\mu C\) which is \(10^{-6}\) of a Coulumb
just plug-in the given in Coulumb's Law formula
so do you have to convert \[muC \] to C before using?
you can also include to the formula such as 1 muC=1(10)^(-6)C...
\[F=\frac{200\times10^{-6}\times400\times10^{-6}}{4\pi\epsilon_0\times d^2}\]
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oops d=5 m
thank you all.
is the answer \[3.56\times10^{-19}N ?\]
k=\[9.0\times10^{9}Nm\]
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