$$x^5 - 7x^3 + 2x^2 - 30x + 6$$

Question

parthkohli · Answer

factor

anonymous · Answer

http://www.wolframalpha.com/input/?i=x5%E2%88%927x3%2B2x2%E2%88%9230x%2B6

parthkohli · Answer

@satellite73 @zepdrix Any idea?

parthkohli · Answer

@Hotchellerae21 If I'd only wanted the answer, I wouldn't have asked it here...

anonymous · Answer

oops sorry :( i was only trying to help

anonymous · Answer

no idea
actually my idea is there is a typo on this question
the polynomial does not factor over the integers as you can see by the zeros

dls · Answer

complex factoring

anonymous · Answer

ok i lied, it does factor

dls · Answer

hahahaha

parthkohli · Answer

I'm frantically searching for the question again...

parthkohli · Answer

Yes, it is correct. WolframAlpha returns$$(x^2 + 3)(x^3 - 10x + 2)$$

dls · Answer

$$\LARGE (x^2 + 3)(x^3 - 10x + 2) =0$$
x=3i
complex solutions

parthkohli · Answer

I know, but how do you factorize?

dls · Answer

u simply dont :P

mathmath333 · Answer

$$x^5-7x^3+2x^2-30x+6$$
split $$(-7x^3=-10x^3+3x^3)$$
$$x^5-10x^3+3x^3+2x^2-30x+6$$
$$x^5-10x^3+2x^2+3x^3-30x+6$$
$$x^2(x^3-10x+2)+3(x^3-10x+2)$$
$$(x^3-10x+2)(x^2+3)$$

parthkohli · Answer

I know how you did that by working backwards.

parthkohli · Answer

How do you work forwards with these kinds of problems though?

mathmath333 · Answer

its tough to say for me...its years i studied polynomials .....as far as i remember surely there is a method i think .
if i found it i will link u

mathmath333 · Answer

its all about the missing $$x^4$$