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Mathematics 21 Online
OpenStudy (anonymous):

How do you simplify this? HELP

OpenStudy (anonymous):

\[\frac{ 1 }{ 2x+3 }+\frac{ 1 }{ x-1 }\]

OpenStudy (kkutie7):

I would start by getting a common denominator. do you know how to do that?

OpenStudy (anonymous):

I tried and I wasn't sure if I had to...foil or...it just didn't work

OpenStudy (anonymous):

\[\frac{ (x-1) }{ (2x+3)(x-1) } + \frac{ (2x-3) }{ (2x+3)(x-1)}\] \[\frac{ (x-1) + (2x-3) }{ (2x+3)(x-1) }\]

OpenStudy (kkutie7):

you basically do that^ cross multiply. there is something you can get rid of in that last equation... can you see it?

OpenStudy (jdoe0001):

the LCD will be, if not easily findable, teh product of the denominators, and then you can simplify it later on

OpenStudy (jdoe0001):

\(\bf \cfrac{ 1 }{ 2x+3 }+\cfrac{ 1 }{ x-1 } \\ \quad \\ \cfrac{[{\color{brown}{ (2x+3)(x-1)}} \div (2x+3)\cdot 1]\quad +\quad [{\color{brown}{ (2x+3)(x-1)}}\div (x-1)\cdot 1]}{{\color{brown}{ (2x+3)(x-1)}}}\)

OpenStudy (anonymous):

Thank you guys!!

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