How do you simplify this? HELP
\[\frac{ 1 }{ 2x+3 }+\frac{ 1 }{ x-1 }\]
I would start by getting a common denominator. do you know how to do that?
I tried and I wasn't sure if I had to...foil or...it just didn't work
\[\frac{ (x-1) }{ (2x+3)(x-1) } + \frac{ (2x-3) }{ (2x+3)(x-1)}\] \[\frac{ (x-1) + (2x-3) }{ (2x+3)(x-1) }\]
you basically do that^ cross multiply. there is something you can get rid of in that last equation... can you see it?
the LCD will be, if not easily findable, teh product of the denominators, and then you can simplify it later on
\(\bf \cfrac{ 1 }{ 2x+3 }+\cfrac{ 1 }{ x-1 } \\ \quad \\ \cfrac{[{\color{brown}{ (2x+3)(x-1)}} \div (2x+3)\cdot 1]\quad +\quad [{\color{brown}{ (2x+3)(x-1)}}\div (x-1)\cdot 1]}{{\color{brown}{ (2x+3)(x-1)}}}\)
Thank you guys!!
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