an object movws along the x-axis with its position x, in meters, given as a function of time t, in seconds, by x(t)=1.39t^2-9.25t+4.68. what is the object's velocity at time t=1.55s ?

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abhisar · Answer

Hello @avemariab93 !
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abhisar · Answer

$\sf Velocity = \frac{\huge dx}{\huge dt}$
=> Velocity = $\sf \frac{\huge d(1.39t^2-9.25t+4.68)}{\huge dt}=2.78t-9.25$.
Now substitute the value of t=1.55 in the equation 2.78t-9.25.

anonymous · Answer

@abhisar omg!! thanks so much!! you're a life saver ^^

abhisar · Answer

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