Question

steps to solving (log base 2 of 4)+(log base 3 of (1/9)) please!

Answer 1

2^2=4
n 3^3=9.
so for first one u get 2

Answer 2

for first part it will be 2(exponent of 2 which gives 4) and for second part, the exponent of 3 that gives 1/9 is -2
so 2-2=0
@jennyneedhelp

Answer 3

\[\log_{2} 4+\log_{3} 1/9\]can be written as\[\log_{2} 2^2+\log_{3} 3^-2\]
now apply formula \[\log_{q} q^p=p \log_{q} q=p\]by using above formula we get
\[2-2=0\]