Question

35x^-2 + 12x^-1 + 1 = 0... Solve for x

Answer 1

There are two possible answers when you work it out..
\(\large\frac{35}{x^2}+\frac{12}{x}+1 = 0\)

Answer 2

I keep misreading the equation, sorry.

Answer 3

Lol its okay...

Answer 4

You're doing great. I posted this problem to see who could get the answer. It's not for me.

Answer 5

Rewrite the left hand side of the equation.
\(1+\frac{12}{x}+\frac{35}{x^2} = 1+\frac{12}{x}+\frac{35}{x^2:}\)
\(1+\frac{12}{x}+\frac{35}{x^2} = 0\)
Write the left hand side as a single fraction.
Bring \(\frac{1+12}{x+35}\div x^2\) together using the common denominator x^2:
\(\frac{x^2+12 x+35}{x^2} = 0\)
Multiply both sides by a polynomial to clear fractions.
Multiply both sides by \(x^2:\)
\(x^2+12 x+35 = 0\)
Factor the left hand side.
The left hand side factors into a product with two terms:
\((x+5) (x+7) = 0\)
Solve each term in the product separately.
Split into two equations:
\(x+5 = 0\) or \(x+7 = 0\)
Look at the first equation: Solve for x.
Subtract 5 from both sides:
\(x = -5\) or \(x+7 = 0\)
Look at the second equation: Solve for x.
Subtract 7 from both sides...

Answer 6

\(x=-7\) or \(-5\)

Answer 7

You're correct...!