How many moles of carbon dioxide are produced when 0.2 mol of sodium carbonate reacts with excess hydrochloric acid?

Question

anonymous · Answer

Na2CO3 + 2HCl ---> 2NaCl + CO2 + H2O

anonymous · Answer

The answer is 0.2 mol and this kind of makes sense but I'm struggling to lay out the reasoning behind it

abmon98 · Answer

$$Na2CO3 + 2HCl \rightarrow 2NaCl + CO2 + H2O$$
1 mole of Na2CO3 reacts with 2 moles of HCl to form 2 moles of NaCl and 1 mole of both CO2 and H2O.
The coefficients in a balanced equation can be used to write a molar ratio.
Molar ratios are conversion factors that can be used to relate:
moles of product formed from a certain number of moles of reactant
1 mole of Na2CO3 :1 mole of CO2
0.2 moles of Na2CO3 : x moles of CO2

anonymous · Answer

Ah I get that! Thanks!

abmon98 · Answer

good to hear that, your most welcome :)