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Chemistry 8 Online
OpenStudy (anonymous):

chem

OpenStudy (anonymous):

i don't know how to start

OpenStudy (aaronq):

Do you know how colligative properties work? Do you know the formula you are to use?

OpenStudy (anonymous):

@aaronq no my book is pretty bad at e xplaining.

OpenStudy (aaronq):

Colligative properties arise from the use of a non-volatile solute in a solvent - in your example ethylene glycol is the solute and water is the solvent. By adding solute, you can raise the BP of a solution. This happens because particles of solute at the solvent-air interface physically block solvent molecules from entering the gas phase - this lowers the vapour pressure of the solution. The more solute you add the higher the BP will be. The formula you are to use is \(\Delta T =i*m*K_b\) where \(\Delta T\) is the change in temperature (from the pure solvent) \(i\) is the van't hoff constant \(m\) is the molality \(K_b\) is the boiling point elevation constant specific to a solvent

OpenStudy (anonymous):

yeah first calculate molality of the solution like molality=weight of solute/molar mass of solute

OpenStudy (aaronq):

that's not the molality equation \(\sf molality=\dfrac{moles_{solute}}{kg_{solvent}}=\dfrac{\dfrac{mass~of~solute}{Molar~mass~of~solute}}{kg_{solvent}}\)

OpenStudy (anonymous):

After that find the change in freezing point \[\Delta Tf = i(Kfm) \]

OpenStudy (anonymous):

ok calculate first what's formula wt for ethylene glycol....

OpenStudy (anonymous):

|dw:1409944122568:dw|

OpenStudy (aaronq):

thats not right. Break it up into steps if it's easier. First find the moles of solute; \(\sf moles=\dfrac{mass}{molar~mass}\)

OpenStudy (anonymous):

|dw:1409945892869:dw|

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