Question

I have a couple questions can someone help me

Answer 1

\[\frac{ 1 }{ (x ^{2}+3)-2 }\]

Im not sure how to simplify this.

Answer 2

hello!! i CAN HELP U OUT..

Answer 3

Okay thank you could you help my with that first question I posted because I dont even know where to start this that one.

Answer 4

start wuth the equation..\[y =mx +c\]

Answer 5

okay should I find the slop in all the tables and put it into that formula?

Answer 6

put values of y and x and find the values of m and c!,,This will get u to the equation

Answer 7

okay I'll try it

Answer 8

yeah! tell me fast..

Answer 9

This is what I did. Did I do it right?

\[m=\frac{ 1-3 }{ 2-5 }=\frac{ -2 }{ -3 }=\frac{ 2 }{ 3 }\]

\[y=mx+b= ......1=\frac{ 2 }{ 3 }+b= \frac{ 1 }{ 3 }\]

Answer 10

and I got\[y=\frac{ 2 }{ 3 }x+\frac{ 1 }{ 3 }\]

Answer 11

nope!..you have to check for two values!...like u found the slope correctly in first table..but now if you choose 2nd and 3rd column to find the slope..it will be different than 2/3

Answer 12

Table 3 is a linear function...u can choose any two columns to find the slope..and ur answer will be same!

Answer 13

get it?

Answer 14

ohhhhh now that makes sense thank you very much

Answer 15

a linear function has a constant slope. this is the whole point of problem

Answer 16

I didnt think of it that way

Answer 17

:)

Answer 18

thank you again(:

Answer 19

dont mention it! :)

Answer 20

mow about your 2nd question...in what way you wanna simplify it?!

Answer 21

**Now

Answer 22

This is the second question that i was having trouble on I kinda got it. This is what I think it is could you check if Im right?
[\frac{ 1 }{ (x ^{2}+3)-2 }\]

Answer 23

\[\frac{ 1 }{ (x ^{2}+3)-2 }\]

Answer 24

how exactly did u do it?! u gave me a doubt..lol! (f.g)(x) is same as f(x).g(x)

Answer 25

well I dont know how to describe it but i kinda put f(x) into f(x)

Answer 26

into g(x)***

Answer 27

haha no!..its wrong!..i think u meant g(x) in f(x) or vice versa..those are different functions they are defines as f(f(x)) or f(g(x))...this is different.get it?

Answer 28

Im so confused lol

Answer 29

wait... Im not here to confuse u! :)