Question

:)

Answer 1

\[\large 12\times1.17^{t}=56\ ...........(1)\]
Dividing both sides of (1) by 12, we get:
\[\large 1.17^{t}=\frac{56}{12}\ ..........(2)\]
Taking logs of both sides of (2) we get:
\[\large t \times \log 1.17=\log 56-\log 12\ ..........(3)\]
Dividing both sides of (3) by log 1.17 we get:
\[\large t=\frac{\log 56-\log 12}{\log 1.17}=you\ can\ calculate\]

Answer 2

Your result for the calculation of t is not correct.
What result do you get for the numerator?
log 56 - log 12 = ?

Answer 3

Good work. That is correct. Now divide that result by log 1.17.

Answer 4

Yes, that is correct.