Question

Finding C and D from finding the anti derivative

Answer 1

\[f^{"}(\theta)= \sin(\theta)+\cos(\theta)\]

Answer 2

\[f'(theta)=-cos(theta)+sin(theta)+C=4\]

Answer 3

\[f(\theta)=-sin(\theta)-cos(\theta)=2\]

Answer 4

this is when \[\theta\] equals zero

Answer 5

You need a theta and f ' value pair
You can't solve for C if you still have theta variable in the equation
What do the original directions say?

Answer 6

Is it theta = 0 for both f ' (0) = 4 and f (0) = 2?

Answer 7

yes.
Is c=5 and d=-2?

Answer 8

First, when you integrate f ' (t), you have to integrate C there too
What does C integrate to?

Answer 9

yeah Sorry I didn't write C in.... I did it in my head though here ya go
\[f(\theta)=-sin(\theta)-cos(\theta)+Cx+D=2\]

Answer 10

Ct there since t is the variable of interest

Answer 11

Check D again...

Answer 12

well...
\[-sin(0)-cos(0)+5+D=2\]
\[0-1+5+D=2\]
\[4+D=2\]
\[D=-2\]
?