Question

A particular strain of bacteria triples in population every 45 minutes. Assuming you start with a 50 bacteria in a petri dish, how many bacteria will there be in 4.5 hours?
A. 33,960
B. 7015
C. 36,450
D. 12,150

Answer 1

This can be modeled as an equation. so start off with y=mx+b

Answer 2

Your Y is what we are trying to identify so it will still be sundown until later

Answer 3

unknown. Sorry

Answer 4

Whoa, it's definitely not unknown!

Answer 5

no i mean the ansewr is found later on.

Answer 6

Initial population times the growth rate to the power of (Time for final answer/ time for r)=total

Answer 7

so r u saying that its 4.5*45+50=x

Answer 8

So \(\huge 5-\times 3^{4.5~hours~ or~270~minutes\div 45}\)

Answer 9

Ignore the "-"

Answer 10

couldnt have done better my self:))))

Answer 11

So \(3^{270\div 45}\) is...?

Answer 12

@mada69 All you :)

Answer 13

my calculator gave me an error.. give me a moment

Answer 14

this is an exponential growth and if you want to put it in linear form, you will have to do some algebraic manipulation

Answer 15

i got 729

Answer 16

that does not look right

Answer 17

Only divide, and it'll fit in. Leave the three alone :P

Answer 18

so i divide the 270 and 6?

Answer 19

270 and 45

Answer 20

cx hehe oops my mistake i meant to say 270/45 cx
i got 6

Answer 21

it is a first-order \[\frac{dN}{dt} = kN\]
N is the number of microbes
t is the time
k is the constant

integrate

Answer 22

There we go :)

Answer 23

Now solve the remaining equation (\(5\times3^6\) and bump a zero on there.

Answer 24

wait i bump in the zero with the 6?

Answer 25

The answer was C :P \(5\times 3^6=3,645\) Add a zero \(36,450\)