Question

Expand (2x-3)^5

Answer 1

heard of binomial theorm ?!!

Answer 2

ok , let a=2x , b=(-3) and n =5
use binomial expantion / theorm to expand

Answer 3

:o
wait u still need help ?
if you dont understand i can explain more

Answer 4

im just going through an idea to see if ur good with it

Answer 5

Okay. I need explanation

Answer 6

have a look here too...


http://www.purplemath.com/modules/binomial.htm

Answer 7

Wait I mean just answer it.

Answer 8

oh sry lol
i dnt bother my self with direct answer :3
i thought ull give the chance to ur self to understand

however go through this
http://prntscr.com/4k51w4

Answer 9

answer :
( 2 x - 3 ) ^ 5
:P

On a serious note, we don't provide just answers, we help you understand if you want, just like what ikram is doing :)

Answer 10

by binomial theorm :-
\(\large (2x-3)^5=\sum _{k=0}^5\binom{5}{k} (2x)^{5-k}(-3)^k \)

Answer 11

\(\large (2x-3)^5=\sum _{k=0}^5\binom{5}{k} (2x)^{5-k}(-3)^k\\
=\binom{5}{0}(2x)^{5}(-3)^0 +\binom{5}{1}(2x)^{4}(-3)^1\\+\binom{5}{2}(2x)^{3}(-3)^2+\binom{5}{3}(2x)^{2}(-3)^3\\+\binom{5}{4}(2x)^{1}(-3)^4+ \binom{5}{5}(2x)^{0}(-3)^5 \)

Answer 12

have to go :3
good luck bhahaha

Answer 13

Okay. Thanks a lot. I got the answer. I just hope this is correct XD. Btw this is not a quiz/test. Its just that I'm exercising myself because our teacher didn't explain it yet.

Answer 14

gr8