how many numers between 1-300 are divisble by 3 but not 5 and 7?
Nevermind, didn't read the question in full. Someone else has got to answer it :)
i would do this by elimination. first there are 100 numbers divisible by 3 next we want to eliminate those that are divisible by 5 5*3 = 15 ---> those numbers must be multiples of 15 300/15 = 20 --> 100 - 20 = 80 now we want to eliminate numbers also divisible by 7 7*3 = 21 --> numbers must be multiples of 21 300/21 rounds down to 14 ---> 80 - 14 = 66 Finally we have to find any numbers which have double counted, divisible by both 5 and 7 3*5*7 = 105 --> these must be multiples of 105 300/105 rounds down to 2 ----> 66 + 2 = 68 There are 68 numbers between 1-300 that are divisible by 3 but not 5 or 7
Thanks alot for solving the Problem
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