The probability that a train leaves on time is 0.7. The probability that the train arrives on time and leaves on time is 0.56. What is the probability that the train arrives on time, given that it leaves on time?
@hartnn @Harsha19111999 @aaronq @Abhisar @am!rah @amistre64

Question

The probability that a train leaves on time is 0.7. The probability that the train arrives on time and leaves on time is 0.56. What is the probability that the train arrives on time, given that it leaves on time? 
@hartnn @Harsha19111999 @aaronq @Abhisar @am!rah @amistre64

anonymous · Answer

@ganeshie8

amistre64 · Answer

assuming independence, there is a nice formula we can apply to this.  can you recall the formula?

haseeb96 · Answer

may i tell him the formula?
@amistre64

amistre64 · Answer

the general setup, yes.  but give them time to think of it and respond with something
that involvement of the asker is key.

anonymous · Answer

I know what to do but, is the answer 0.8 correct??? @amistre64 @Haseeb96

amistre64 · Answer

we cal always dbl chk with the setup :)

.56/.7 = 5.6/7

.8 seems appropriate yes

anonymous · Answer

thanks to you both

amistre64 · Answer

$$P(A~given~B)=\frac{P(AnB)}{P(B)}$$

haseeb96 · Answer

thanks only amister 
because he is teacher

amistre64 · Answer

in other words, the outcomes of A that are in B, when compared to B being the outcomes

anonymous · Answer

thanks for the knowledge