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Linear Algebra 7 Online
ganeshie8 (ganeshie8):

Prove that \(f_1(x)=1,f_2 (x)=x,f_3 (x)=((3x^2-1))/2\) are orthogonal over \((-1,1)\) using matrices

ganeshie8 (ganeshie8):

@OOPS

OpenStudy (anonymous):

I answered. :) and I am sure you got it. hihihi

ganeshie8 (ganeshie8):

you have deleted it before reading it completely

ganeshie8 (ganeshie8):

i know onlhy linear algebra, never took abstract... so im not good with fields but i can read wiki for keywords if you show me the matrix method :)

OpenStudy (anonymous):

It's not hard, friend, that from theoretical linear algebra, not abstract any polynomial is in the form a + bx + cx^2 + dx^3+.......

ganeshie8 (ganeshie8):

okay...

OpenStudy (anonymous):

so that {1, x, x^2, x^3,......} is the basis of polynomial set Consider P_2, we have basis of P_2 is {1, x,x^2}

ganeshie8 (ganeshie8):

please wait, so basis is a set of linear independent vectors that span the entire vector space, right ?

ganeshie8 (ganeshie8):

it seems like you're defining a basis whose dimension is infinite or something

OpenStudy (anonymous):

so that the first one is 1 + 0x + 0x^2 the second is 0+1x +0x^2 the third is -1/2 +0 x+ 3/2 x^2 and Yes for your question

OpenStudy (anonymous):

P_2 is subset of P, and Wolg P is a vector space

OpenStudy (anonymous):

from that I can construct the matrix as shown.

ganeshie8 (ganeshie8):

I see...

OpenStudy (anonymous):

And it 's quite easy to prove they are independent vectors and then orthogonal.

ganeshie8 (ganeshie8):

this would be the matrix \[\large \left[\begin{array}\\ 1&0&0\\0&1&0\\-1/2&0&3/2 \end{array}\right]\] ?

OpenStudy (anonymous):

yes

ganeshie8 (ganeshie8):

we need to show determinant is 0 for independence

ganeshie8 (ganeshie8):

what about orthogonality ?

ganeshie8 (ganeshie8):

*not 0

OpenStudy (anonymous):

using inner product

OpenStudy (math&ing001):

If you show that rank of the matrix =3 it should solve the problem.

OpenStudy (anonymous):

f1 dot f2 =0 and so on...

hartnn (hartnn):

orthogonal \(AA^T =I\)

ganeshie8 (ganeshie8):

Sweet :3

ganeshie8 (ganeshie8):

this looks more elegant than the integrals xD

OpenStudy (anonymous):

Yes, there are many ways, but I choose the simplest way for my simple brain

ganeshie8 (ganeshie8):

just a final noob question : we need to take inner product of pairs of \(column\) vectors right ?

OpenStudy (anonymous):

I use row, not column

OpenStudy (math&ing001):

It's the same but always go with the easiest.

ganeshie8 (ganeshie8):

row space is orthogonal <==> column space is orthogonal ?

OpenStudy (anonymous):

The reason I choose row is (1,0,0) is the first vector as f(1), so that it makes more sense than picking (1,0,1/2) where I don't know what it stands for.

OpenStudy (anonymous):

and I need prove f(1) perpendicular to f(2) and f(3) . That 's it

OpenStudy (math&ing001):

If you take it as a 3*3 matrix yes, you can use columns or rows.

ganeshie8 (ganeshie8):

Oh I see... i think i get it :) thanks !

OpenStudy (anonymous):

:)

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