Question

For f(x) = 1/2x, determine
a) f(1)- f(3)
b) f(1/4) + f(3/4)

Answer 1

Plug in 1, 3, 1/4, and 3/4 into that equation

Answer 2

When you get 1 and 3. Subtract your answer f(3) from f(1)
When you get 1/4 and 3/4, Add you answer for f(1/4) and f(3/4)

Answer 3

I get 1/2 - 1/6

Answer 4

1/2 multiplied by 3 means that you would multiply 3 by 1, but keep the 2 at the bottom. So, A would be 1/2-3/2

Answer 5

confuse

Answer 6

Is \(\large f(x) = \frac 12x\) or \(\large f(x) = \frac{1}{2x}\) ?

Answer 7

the second one is corrcet

Answer 8

for the f(1) I get like 1/2

Answer 9

and for the f(3) I get 1/6

Answer 10

\[
f(x) = \frac {1}{2 x} \\
f(1) = \frac {1}{2*1} = \frac 12 \\
f(3) = \frac {1}{2*3} = \frac 16 \\
f(1) - f(3) = \frac 12 - \frac 16 = \frac 36 - \frac 16 = \frac {3-1}{6} = \frac 26 = \frac 13
\]

Answer 11

then I think we have to subtrtact 1/2 - 1/6

Answer 12

why did you write 1/3 it be only 3

Answer 13

\(\Large \frac 12 - \frac 16\). Find the least common denominator which is 6.
Make the denominator 6. So multiply top and bottom of \(\Large \frac 12\) by 3:
\(\Large \frac 12 = \frac{1*3}{2*3} = \frac{3}{6} \)

\(\Large \frac 12 - \frac 16 = \frac 36 - \frac 16\).

If the denominators are the same, the numerators can be combined:

\(\Large \frac 36 - \frac 16 = \frac{3-1}{6} = \frac 26 = \frac 13\)

Answer 14

Go through some online examples and YouTube videos on adding and subtracting fractions.

Answer 15

https://www.khanacademy.org/math/cc-fifth-grade-math/cc-5th-fractions-topic/cc-5th-add-sub-fractions/v/adding-fractions-with-unlike-denominators

Answer 16

I have to log out now.

Answer 17

ok but what about the part b

Answer 18

\[
f(x) = \frac {1}{2 x} \\
f(1/4) = \frac {1}{2*1/4} = \frac {1}{1/2} =2 \\
f(3/4) = \frac {1}{2*3/4} = \frac {1}{3/2} = \frac 23 \\
f(1/4) + f(3/4) = 2 + \frac 23 = \frac{6+2}{3} = \frac 83
\]