Derive the equation of the parabola with a focus at (−5, 5) and a directrix of y = -1.
(-5,5)
f(x) = −one twelfth (x − 5)2 + 2 f(x) = one twelfth (x − 5)2 + 2 f(x) = −one twelfth (x + 5)2 + 2 f(x) = one twelfth (x + 5)2 + 2
all those diamond things are supposed to be ( - ), i don't know why they show up like that
thought it was the third one but it was wrong too
Given two points, the focus (-5,5) and the directrix (x, -1), plug both points into this formula: \((x - x_1)^2 + (y - y_1)^2 = (x - x_2)^2 + (y - y_2)^2\) Then simplify
\[(-5 - x)^2 + (5 - 1)^2 = (-5 - x)^2 + (5 - 1)^2 \] What did I do wrong here? I come up with zero
You're only supposed to plug the values for \((x_1, y_1)\) and \((x_2, y_2)\)
\((x_1, y_1)\) = (-5, 5) \((x_2, y_2)\) = (x, -1)
Ok so (x - x1)^2 + (y - y1)^2 = (x - x2)^2 + (y - y2)^2 (x - 5)^2 + (y - 5)^2 = (x - x)^2 + (y - 1)^2 Is it like this \[(x - 5)^2 + (y - 5)^2 = (x - x)^2 + (y - 1)^2 \] or this \[(x + 5)^2 + (y - 5)^2 = (x - x)^2 + (y + 1)^2\] I feel like I'm plugging these in wrong. :/
\((x + 5)^2 + (y - 5)^2 = (x - x)^2 + (y + 1)^2\) is correct. Try to understand why.
Because two ( - ) make a ( + )
Okay, now what can we do next?
simplify
Simplify what?
Umm the expression? or it doesn't need simplifying?
It has to be simplified. I was just asking about your simplification plan? How are you going to approach simplifying this?
@CrazyTurtle483, you still here?
Yes sorry my dad wanted me to go get something
Ok honestly i really tried to simplify this but i dont understand where to start \[(x + 5)^2 + (y - 5)^2 = (x - x)^2 + (y + 1)^2 \]
+ x or do a +5?
Start with \((x - x)^2\) Obviously x - x = 0
makes sense
and 0^2 = 0
Next, subtract \((y - 5)^2\) from both sides
(x + 5)^2 + (y - 5)^2 = (y + 1)^2 - (y - 5)^2 - (y - 5)^2 (x + 5)^2 = 12y − 24?
\[(x + 5)^2 = 12y - 24\] I don't know why there are diamonds
Show me how you got from \((y + 1)^2 - (y - 5)^2\) to 12y - 24
I didn't know what (y+1)^2 - (y-5)^2 was so i distributed and combined like terms
What do you mean? Explain your algebraic steps.
since youre asking about 12y -24, is that wrong? i dont know what (y+1)^2 - (y-5)^2 equals.. distribute y^2 + 2y + 1 + − y^2 + 10y + −25 then you combine the like terms (2y + 10y) + (y2 - y2) + (1 + -25) 12y + -24
Actually, instead of expanding what you do is use the difference of squares formula
\[y^2 + 2y + 1 + −y^2 + 10y + −25 \]
i havent learned that yet
Are you saying you don't know how to factor \(y^2 - 4\) ?
(y + 2) (y - 2) ?
Exactly I know that you know the difference of squares
didn't know factoring was also called difference of squares haha
ok so \[(x+5)^2 = (y+2)(y-2) ? \]
Difference of Squares is \(a^2 - b^2 = (a + b)(a - b)\)
\(y^2 - 4 = y^2 - 2^2 = (y + 2)(y - 2)\)
\((y + 1)^2 - (y - 5)^2 = (y + 1 + y - 5)(y + 1 - (y - 5))\)
and \((y + 1 + y - 5))(y + 1 - (y - 5)) = (2y - 4)(6) = 12y - 24\)
Either way, 12y - 24 is correct
Now all you have to do is just continue solving for y
ok so would it be 6(2y - 4) = 12y - 24
then what because don't you distribute next?
Isolate y
What you have left is \((x + 5)^2 = 12y - 24\)
ok but then what, isn't y isolated? or 12y - 24 y = 2
You don't know how to isolate y from there?
Add 24 to both sides. Afterwards, divide both sides by 12
(x+5)^2 = 12y - 24 +24 +24 ok so youre left with 12y one one side but what is (x+5)^2 + 24?
i feel like i should know this better
\[\frac{ 1 }{ 12 } (x+5)^{2} + 2 ? \]
you there @Hero
Looks right
Yay it was!
thank you so much man, you are one of the most patient people ive ever met
We don't stop until it's done and right.
Most people would probably have given up on me haha, thanks again.
No, it wasn't that bad.
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