Question

Please, help
I don't understand why they got that answer for this problem.
My solution is in comment

Answer 1

http://www.math.niu.edu/~beachy/abstract_algebra/study_guide/soln23.html#s2316

Answer 2

for this calculation: (3,8,7)(1,7,9)(3,11,5,6,8,10)(3,7,8)
I got (1,8,11,5,6,3,9)(7,10) whose order is 14. I don't know how to get their answer.

Answer 3

Oh, I got their answer but my question on it is :
is not that \(\sigma * \tau * (\sigma)^- \) must be go this way:
Calculate \(\tau * (\sigma^-)\) first, then times to \(\sigma \) in the front?
How can we break \(\tau\) function into 2 pieces and calculate as they do??

Answer 4

i kinda forget, but you do read from right to left i think

Answer 5

If I break it to parts like that, I get exactly what they get. But if I do step \(\tau *\sigma^-\) then \(\sigma *\tau*\sigma^-\) I get another answer like what I post in the first comment.
They should be the same, right?

Answer 6

i guess if you do it in the right order
composition is not commutative

Answer 7

No, the disjoint cycles are commutative.

Answer 8

And each of them is disjoint.

Answer 9

i am not sure what you mean
you are composing them
it is not the case that \(\sigma \tau=\tau \sigma\)

Answer 10

I will scan and post my calculating. Please, check then. :)

Answer 11

ok

Answer 12

@satellite73 I am sorry. I carelessly calculated. Now, I got the same answer with them. Hihihi. Thanks for being patient.