insert grouping symbole in the expression so that the value of the expression is 14
1. 9+39+22/11-9+3
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OpenStudy (petiteme):
There xD
OpenStudy (jamanorthi):
@petiteme yeah
OpenStudy (petiteme):
\[\frac{ 9+39+32 }{ 11-9+3}\]
Since the numerator is all addition, you can just add it all.
So it'll be
\[\frac{ 70 }{ 11-9+3 }\]
Look at the denominator. What if you group it like this:
11-(9+3)
Will you get 12? Or if you group it like this:
(11-9) + 3
OpenStudy (jamanorthi):
okay let me solve it now
OpenStudy (petiteme):
Okay. I'll wait ^_^
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OpenStudy (jamanorthi):
@petiteme i don't get it
OpenStudy (petiteme):
Okay lemme help you out.
To get 14 as an answer, try solving this first.
\[\frac{ 70 }{ (11-9) + 3 }\]
That's out first trial of grouping.
OpenStudy (jamanorthi):
okay
OpenStudy (jamanorthi):
70/23
OpenStudy (petiteme):
Wrong. The first thing to do is perform the operation inside the parenthesis :)
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OpenStudy (jamanorthi):
okay
OpenStudy (petiteme):
I'll wait ^_^
OpenStudy (jamanorthi):
i am so confused
OpenStudy (petiteme):
Okay. Do (11-9) and then when you get the answer, add it to 3.
OpenStudy (jamanorthi):
5
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OpenStudy (petiteme):
Good! Then 5 will be your denominator right?
\[\frac{ 70 }{ 5 }\]
So 70 divided by 5 is 14 right?
OpenStudy (jamanorthi):
yeah it is
OpenStudy (petiteme):
So the grouping that you need is
\[\frac{ (9+ 32) + 22 }{ (11-9) + 3 }\]
OpenStudy (jamanorthi):
okay thanks
OpenStudy (petiteme):
You're welcome :) I hope I helped you out.
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