The arithmetic mean of two numbers is 18. Their geometric mean is 16. Find the sum of the squares of the two numbers.
arthemtic mean is \[(x+y)\div2\]=18 and geometric mean is xy=16 solve these equations for x and y
what does it mean by the sum of the two squares?
the sum of the two squares basically means that the sum of the two numbers after they have been squared.
so far I have \[a+b=36\] & \[ab=256\] my teacher said that the geometric mean is\[\sqrt{ab}\]
hey sry its \[\sqrt{xy}\]
they mean \[x^{2}+y^{2}\]
then u have a+b square it
it will be \[a^{2}+b^{2}+2ab\]
use ur values to obtain solution
\[\left( 36 \right) \left( a^2+512+b^2 \right)\] is this the right equation?
[36^{2}=a^{2}+b^{2}+512\]
therefore, \[a^2+b^2=784\]
haa....thats all hope u understood the solutionn
Yes, thank you so much!
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