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OpenStudy (anonymous):
The arithmetic mean of two numbers is 18. Their geometric mean is 16. Find the sum of the squares of the two numbers.
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OpenStudy (anonymous):
arthemtic mean is \[(x+y)\div2\]=18
and geometric mean is xy=16
solve these equations for x and y
OpenStudy (anonymous):
what does it mean by the sum of the two squares?
OpenStudy (anonymous):
the sum of the two squares basically means that the sum of the two numbers after they have been squared.
OpenStudy (anonymous):
so far I have \[a+b=36\] & \[ab=256\]
my teacher said that the geometric mean is\[\sqrt{ab}\]
OpenStudy (anonymous):
hey sry its \[\sqrt{xy}\]
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OpenStudy (anonymous):
they mean \[x^{2}+y^{2}\]
OpenStudy (anonymous):
then u have a+b square it
OpenStudy (anonymous):
it will be \[a^{2}+b^{2}+2ab\]
OpenStudy (anonymous):
use ur values to obtain solution
OpenStudy (anonymous):
\[\left( 36 \right) \left( a^2+512+b^2 \right)\] is this the right equation?
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OpenStudy (anonymous):
[36^{2}=a^{2}+b^{2}+512\]
OpenStudy (anonymous):
therefore, \[a^2+b^2=784\]
OpenStudy (anonymous):
haa....thats all
hope u understood the solutionn
OpenStudy (anonymous):
Yes, thank you so much!
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