Ask your own question, for FREE!
Mathematics 15 Online
OpenStudy (anonymous):

Express the surface area of a cube as a function of its volume

OpenStudy (ahsome):

Whoops, ignore me

OpenStudy (ahsome):

Function of surface area of cube: \[s(x)=6x^2\] Function of volume of cube: \[v(x)=x^3\]

OpenStudy (ahsome):

s(x)=\[s(x)=\frac{ x^3 }{ x }*6\]

OpenStudy (dumbcow):

a cube has volume of x^3 cube has 6 sides each with area of x^2 --> 6x^2 so we have: v= x^3 A = 6x^2 solve for x in 1st equation \[x = \sqrt[3]{v}\] sub into 2nd equation \[A = 6 (\sqrt[3]{v})^2 = 6 v^{2/3}\]

OpenStudy (ahsome):

@ernesto22 Do you understand?

OpenStudy (anonymous):

why couldn't we just sub x^3 into 6x^2 to get 6x^6?

OpenStudy (dumbcow):

because we want it in terms of "v" also that is an invalid substitution .... x does not equal x^3

OpenStudy (anonymous):

so we are trying to find SA(v) correct?

OpenStudy (ahsome):

Also, you are trying to EXPRESS, not SOLVE

OpenStudy (anonymous):

we are trying to find Sa(V) correct?

OpenStudy (dumbcow):

yes

OpenStudy (anonymous):

but we already know that the volume is equal to x^3, so why is it not valid to just sub it into 6x^2?

OpenStudy (anonymous):

Oh, i figured it out! thank you very much :)

OpenStudy (dumbcow):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!