Question

Please help me out. :(

A stone is tossed upward at the moment a ball is dropped from a height of 30 m. The stone's initial velocity is 20 m/s. At what height will the two meet? At what time will they meet?

Answer 1

First try to picture the situation, or draw it on paper

Answer 2

ahh. then?

Answer 3

What have you done so far? With both stone and ball, the appropriate equation of motion is \[v=v _{0}+at,\]where a = acceleration = -9.8 meters per second squared.

Answer 4

Since the initial height of the ball is given (30 meters), we also need an equation of motion that involves that initial height. It is \[s=s _{0}+v _{0}t+\frac{ 1 }{ 2 }at^2\]

Answer 5

Please look at the information you're given, then look at these two equations. You may need to go through two or more steps towards finding the time at which the two objects will hit one another in space and then the height off the ground of the two when they hit.

Answer 6

when we will use s = u^2 + (at^2)/2 ?

Answer 7

i really don't understand this one..

Answer 8

Do you agree
Displacement covered by the first stone + Displacement covered by second stone = 15

Answer 9

how come?

Answer 10

just think , imagine you drop a apple from a tree , and also toss a ball up , they will meet only when they cover a total height of the tree , whatever their speeds maybe

Answer 11

ahh.. got it.. i'll try to solve it again..

Answer 12

See it doesn't matter whatever theyre speeds maybe they should together cover the total height
if they don't cover then they aren't going to meet