Vector Question
Question 14, thanks
Who can help?
a rhombus is a parallelogram (i.e. opposite sides are parallel) with all sides being the same length.
Given \[ \vec{OA}=\vec{a}\\ \vec{OC}=\vec{c}\\\vec{BD} = k \vec{BA} \] Using the fact we have a rhombus: \[ \vec{CB}=\vec{OA}= \vec{a} \] and for the same reason \[ \vec{BA}= \vec{CO}= -\vec{OC}= -\vec{c}\] and so (using this and the given): \[ \vec{BD} = k \vec{BA} = -k\vec{c}\] meanwhile, for point D we want to go from OC to CB to BD \[D= \vec{c}+\vec{a}-k\vec{c}\] and the vector we want is \[ \vec{CD}= D-C=\vec{c}+\vec{a}-k\vec{c} - \vec{c} \\= \vec{a}-k\vec{c}\]
Wow, I understand now, but how can I find the value of k?
There are a few ways. maybe the easiest is to use geometry |dw:1410111338264:dw|
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