Question

@ganeshie8 @waterineyes @rational @phi

Answer 1

The horizontal asymptote(s), if any, would be:


Select one:
a. y = 4 and y = 0
b. y=1/4
c. y = 4
d. No horizontal asymptotes

Answer 2

what do you know about horizontal asymptotes of a rational function ?

Answer 3

http://www.coolmath.com/precalculus-review-calculus-intro/precalculus-algebra/18-rational-functions-finding-horizontal-slant-asymptotes-01.htm

Answer 4

so what would be the horizontal asymptotes in this one

Answer 5

you tell meh

Answer 6

would it be y=4 or y=1/4

Answer 7

this is your problem, not mine
so you need to struggle a bit and get a feel of the problem first :)

Answer 8

are you guessing them because they're there in the options ?

Answer 9

ok thanks for the help

Answer 10

how did you get y=4 ?

Answer 11

I guessed of course because I don't know how to do this

Answer 12

thats exactly why i am here,
this is an easy problem unline the other problems on factors/zeroes you have worked earlier

Answer 13

people on thi site spend like 5 hour on one question

Answer 14

lets see how to find the horizontal asymptotes

Answer 15

and why do they spend so much time ? are you paying them ?

Answer 16

WHAT??? NVM lets get this question done then

Answer 17

where are you stuck on this question ?
did u open the link i gave u earlier ?

Answer 18

yea and it didnt help that's why I guessed so I could see if I got it wrong or not but you didn't tell me

Answer 19

be specific, which part in that link looks hard to interpret ?

Answer 20

To get a quick answer, you need to ask directed questions that show your understanding; for example :

` I understand that they are checking for degree of numerator and denominator. So what exactly is a degree ?`

Answer 21

Ive always had troubles with finding the asymptotes

Answer 22

simply saying `it didnt help` or `people are taking 5 hours to work a question` wont tell others what exactly is your problem

Answer 23

Okay, what is an asymptote ?

Answer 24

a straight line approached by a given curve as one of the variables in the equation of the curve approaches infinity.

Answer 25

you need to know atleast the definition of an asymptote before trying to find them, eh ?

Answer 26

I just posted it

Answer 27

thats right !

Answer 28

\[\large y = \dfrac{4x^2+12x}{x^2+x-6}\]

Answer 29

can you tell me the degree of numerator ?

Answer 30

im not sure:(

Answer 31

thats okay, degree is simply the HIGHEST exponent

Answer 32

\[\large y = \dfrac{4x^{\color{Red}{2}}+12x}{x^2+x-6}\]

Answer 33

degree of numerator = \(\color{Red}{2}\)

Answer 34

can you guess the degree of denominator ? (bottom)

Answer 35

the degree for the bottom would be two also right

Answer 36

sorry OS keeps reloading for me

Answer 37

yes both degrees are same

Answer 38

so now what doi doo

Answer 39

we're almost done. just the last step

Answer 40

open the link i gave u earlier,
it tells you what needs to be done when degrees are same

Answer 41

ok

Answer 42

you just need to take ratio of leading coefficients

Answer 43

\[\large y = \dfrac{\color{red}{4}x^2+12x}{\color{Red}{1}x^2+x-6}\]

Answer 44

horizontal asymptote would be :

\[\large y = \dfrac{\color{Red}{4}}{\color{Red}{1}}\]

Answer 45

so would be y= 4 basically

Answer 46

which is same as

\[\large y = \color{red}{4}\]

Answer 47

Yep !

Answer 48

thanks im sorry I got mad for the direct answers

Answer 49

I know its not efficient to spend 30 minutes on one question. You must be having so many problems and other subjects also to work... But it becomes easy+fast once you know some basics :)