1
oh, no, just 1
I am sorry for misread the problem. My final answer is only one
I wanna understand how to approach the answer
Let me retype it
i really dont get it
A is invertible --> the transformation is one to one which means any image has only 1 preimage. Your image is b, its preimage is x
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A is applied to x to get b, you have Ax =b
If you can prove that A is invertible, then A transfers x to b and then \(A^-\) transfers b back to x, not other point
so that, for each b, you have only 1 x
The goal of the problem becomes proving A is invertible.
How to know? det A \(\neq 0\) --> A is invertible.
and you can calculate det A = 3 \(\neq 0\)
which leads to A is invertible
--> each b has only 1 x
this is the question, they are vectors. So I still can't follow you somehow. We have not reached the invertible part yet.
wow!!
if you don't know what is invertible, how you can solve a general problem like this???
@rational Please, help
Sorry...maybe I do know what invertible means I might not know that the concept is called invertible
hihihi ... That's all I can give you. Reread and you can understand it.
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