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Mathematics 21 Online
OpenStudy (anonymous):

.Identify the sequence graphed below and the average rate of change from n = 1 to n = 3 an = 8(one half)n − 2; average rate of change is −6 an = 10(one half)n − 2; average rate of change is 6 an = 8(one half)n − 2; average rate of change is 6 an = 10(one half)n − 2; average rate of change is −6

OpenStudy (anonymous):

OpenStudy (anonymous):

@satellite73

OpenStudy (anonymous):

that is a lot of words let me see if i can figure them out

OpenStudy (anonymous):

Okay c:

OpenStudy (anonymous):

pattern is pretty clear right? \[8,4,2,1,...\] you are dividing by 2 each time so since you have \((2,8)\) on the graph, it is a good guess that \((1,16)\) is on there also even though you don't see it

OpenStudy (anonymous):

Oh, Yeah. So i know the rate of change formula so do i d. \[\frac{ 4-16 }{ 3-1 }\]

OpenStudy (anonymous):

zactly

OpenStudy (anonymous):

That would be -12/2. Which would be -6. ;o so its either A or D.

OpenStudy (anonymous):

you could probably have guessed that is was negative anyways, since it is going down right , that leaves A, D

OpenStudy (anonymous):

without doing any more work you can probably guess it is A since there is not \(10\) involved with this, but we can check that it is right

OpenStudy (anonymous):

Oh, Thaaank you c:

OpenStudy (anonymous):

\[a_n=8\times \left(\frac{1}{2}\right)^{n-2}\] if say \(n=3\) then you get \[a_3=8\times \left(\frac{1}{2}\right)^{3-2}=8\times \left(\frac{1}{2}\right)^1=8\times \frac{1}{2}=4\]

OpenStudy (anonymous):

yw

OpenStudy (anonymous):

Oh, that makes sense :3

OpenStudy (anonymous):

works for the others as well

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