Question

A large capacitance of 1.60 mF is needed for a certain application.

(a) Calculate the area the parallel plates of such a capacitor must have if they are separated by 4.00 µm of Teflon.
m2
(b) What is the maximum voltage that can be applied?
V
(c) Find the maximum charge that can be stored.
C
(d) Calculate the volume of Teflon alone in the capacitor.
m3

Answer 1

use the following formula:\[C=\epsilon_0\frac{A}{d}\]C is capacitance, Farad
A is the area of the plate
d is the distance between plates
\(\epsilon_0\) is the dielectric constant of the material, Teflon in this case

Answer 2

you should use simply \[\epsilon \]

Answer 3

yes it is supposed to be\[\epsilon=\epsilon_r\epsilon_0\]where \(\epsilon_r\) is the relative permittivity of the material and \(\epsilon_0\approx8.854\times10^{-12}~F~m^{-1}\)
... thanks for the correction @tony115

Answer 4

thank you @orion1213

Answer 5

I'm wondering if you need to know the dielectric strength of the teflon to answer part (b) - was that information provided in the question ?

Answer 6

Teflon constant k is 2.1 and dialectic is 6e6

Answer 7

part a should be straightforward - what is the thickness of the teflon, the units have come out weird in the question ?