Question

PLEASE HELP!!
1. A soccer player kicks the soccer ball straight up with a velocity of 17 m/s.
Using a distance versus time graph:
How long is the ball in the air?

Using a velocity versus displacement graph:
How high does it rise?

2. A dart is dropped from a height of 4.12 meters.
Using a distance versus time graph
How long is the dart in the air?

Answer 1

Are you expected to graph them or is there a diagram associated with this question?

Answer 2

It's a graph

Answer 3

Can you post the graphs? Post a screenshot of the question.

Answer 4

But it doesn't even show the graph... It just says Using a distance verses time graph: (whole sentence underline) and that's it

Answer 5

I'm guess I'm supposed to do equations, but I'm so confused

Answer 6

The formula is: \(y = ut - \frac 12 gt^2 = 17t - \frac 12 * 10 * t^2 = -5t^2 + 17t\)
Graph y vs t.
The x-intercept of the graph, other than t = 0, will be how long the ball stays in the air.

Answer 7

Oh that makes a bit more sense now. I just need the equation

Answer 8

Could you also explain the rest, please?

Answer 9

Have you done calculus yet?

Answer 10

I'm currently in Trig and Analysis of Functions...

Answer 11

Have you covered the equations in Physics?

Answer 12

I know the kinematics and -9.8 m/s^2 is gravity and that's about it

Answer 13

the delta and stuff

Answer 14

\(v^2 = u^2 - 2gx = 17^2 - 2*10*x = -20x + 289\)

\(v = \sqrt{-20x + 289}\) where v is the velocity and x is the displacement (vertical height of the ball). I chose x because they want a plot of v vs displacement and so x for displacement will be convenient and v will go along the y-axis.

Draw a graph of v vs x.

When the ball reaches the maximum height, velocity v = 0. So the x-intercept of the graph will give the maximum height reached by the ball.

PS: I am using g = 10 m/s^2