Let X = “I am happy,” let Y=“I am watching a movie” and Z=“I am eating spaghetti.” Translate the following statements into words.
(Y→ ¬X)∧(Z→ ¬X) would that be "If I am watching a movie, then I am not happy, and if I am eating spaghetta, then I am not happy," Or "If I am watching a movie then I am not happy, and if I am eating spaghetta then I am not happy,"
oops hold on
Question marks?
\[(Y\rightarrow \neg X)\wedge(Z\rightarrow \neg X)\]
Sorry about that.
I'm not sure how to use comma correctly...
@campbell_st @Ashleyisakitty @jim_thompson5910 Can you help?
if X is happy, then -X is not happy.
so the second one you said.
why not also first one? what's wrong with it?
that would be \((Y \implies X)\)
the - means not. so if x not y i.e. if im watching a movie i am NOT happy
I get the negation part, but not coma and how they affects statement... What's the difference between \(\longrightarrow\) and \(\Longrightarrow\)?
comma*
nothing
So first one is also right?
comma?
Yes, this one: \(\Huge ,\)
the first one is not right, it would be \((Y\rightarrow X)\wedge(Z\rightarrow X)\)
Umm, I did insert not...
1: "If I am watching a movie, then I am not happy, and if I am eating spaghetta, then I am not happy," 2: "If I am watching a movie then I am not happy, and if I am eating spaghetta then I am not happy,"
ahhh i see what you are asking
sec
this is more of a grammar question...
yeah, I just want to know whether comma being presented before "then" has impact on statement or not
I think they are the same in this context. This is not how anyone would say this sentence but we are modeling math...
okay, so maybe start another question and ask question more specifically?
yeah I guess
sure, maybe in the writing area.
either way you did NOT write if I am watching tv, then I am not happy and I am eating spaghetti then I am not happy.
that would be the WRONG way to interpret this
Yeah, I understand, because it would goes back to \(Y\rightarrow(\neg X\wedge(Z\rightarrow\neg X))\), right?
exactly
gotcha. well thanks for help
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