:)
so im a little lost here... what is the question exactly?
i think you need calcule the lenght of FH so for this you can using sin 40° = ?
well i believe that you have it sketched correctly ... as for the other parts of the question you should give us your final answer or if you need help being walked through the steps you could ask that but i do believe that you have the triangle sketched correctly!
1. Your sketch is correct. 2. To find the length of FH, use the Law of Cosines: \((FH)^2 = (GF)^2 + (GH)^2 - 2(GF)(GH)\cos(FGH) \) \(FH^2 = 7^2 + 10^2 - 2(7)(10)\cos(40) = ? \) Take square root to find FH. 3. To find angle GFH, use the Law of Sines: \(\Large \frac{\sin(GFH)}{10} = \frac{\sin(40)}{FH}\) \(\sin(GFH) = 10 \times \Large \frac{\sin(40)}{FH}\) Substitute FH found in part 2 and solve for angle GFH. The third angle of the triangle can be found by using the fact the three angles of a triangle add to 180 degrees.
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