Find the derivative of this function
g(x) = x^2-2x + 5/x
This is what I got
f(x) = (X^2 - 2X +5) f' (x) = (2x -2 +5)
g(x) = (x) g'(x) = 1
g'= (2x -2 +5) (x) -1 (x^2- 2x +5)/ (x+1)
Get you help to tell me if I am in the right direction.....

Question

Find the derivative of this function
g(x) = x^2-2x + 5/x
This is what I got 
f(x) = (X^2 - 2X +5)        f' (x) = (2x -2 +5)
g(x) = (x)                         g'(x) = 1
   g'= (2x -2 +5) (x) -1 (x^2- 2x +5)/ (x+1)
Get you help to tell me if I am in the right direction.....

anonymous · Answer

Rewrite it as g(x)= x^2 -2x + 5x^-1

anonymous · Answer

$$\frac{ x^2-2x + 5 }{ x }$$
Need to find the derivative of this problem

anonymous · Answer

Simplify it or do the quotient rule. I would do (x^2/ x) - (2x/x) + 5/x which ends as x-2+5x^-1

anonymous · Answer

g(x) = x-2+5x^-1 
g'(x) = 1-5x^-2 
g'(x) = 1-(5/x^-2)