Question

I keep making a mistake somewhere and have no idea where
Find the slope of the function at the given value
y=-(-x+2)^ (1/2) at x=-5

Answer 1

WE HAVE NOT LEARNED DERIVATIVES YET FYI. We will be getting to them in a day or so, but we haven't actually learned them yet. Just the fundamental theorem thing with f(a+h) and whatnot

Answer 2

@ganeshie8

Answer 3

@jdoe0001

Answer 4

@aaronq

Answer 5

@DangerousJesse @dan815

Answer 6

http://www.math.brown.edu/utra/tangentline.html

Answer 7

The answer is -3

Answer 8

Oh wait

Answer 9

wrong problem

Answer 10

It is actually root 7 over 14

Answer 11

Which is worse

Answer 12

o.e lel
goo luck with that x3

Answer 13

thanks >.>

Answer 14

If you know anyone that can help, by all means

Answer 15

ummm...will....i think that my bro and ex know how to work these stuff o.e
but ik that they wont help sorry :/

Answer 16

lol thanks anyways

Answer 17

np ^^

Answer 18

@Hero

Answer 19

@UnkleRhaukus

Answer 20

@robtobey

Answer 21

@iambatman

Answer 22

@Hero

Answer 23

Refer to the plot and solution calculated by Mathematica 9 Home Edition.

Answer 24

We haven't gotten to derivatives yet. Just tangent and secant lines. Is it even possible with just that?

Answer 25

It has been so long since I've been in school, that I can't remember either way.
Sorry.

Answer 26

Awww....

Answer 27

@jim_thompson5910

Answer 28

you're familiar with this equation right?

\[\Large f^{\prime}(x) = \frac{f(x+h)-f(x)}{h}\]

Answer 29

Yes

Answer 30

we know f(x)

f(x) = -(-x+2)^ (1/2)

what is f(x+h) equal to?

Answer 31

f(x+h)=f(-5+h)= -(-(-5+h)+2)^1/2

Answer 32

don't plug in x = -5 yet

Answer 33

oh

Answer 34

I'll let you know when that part comes

Answer 35

well it equals -(-(x+h)+2)^1/2

Answer 36

good

Answer 37

I'm going to convert the 1/2 power to a square root

since x^(1/2) = sqrt(x)

Answer 38

Yep

Answer 39

so we have this so far