Question

have another question:

predict products and write a balanced chemical equation for the reactions below. include the physical states of the products in your equation.

1. H2SO4 (aq)+Ba(OH)2(aq)

2. HC2H302(aq)+NH3(aq)

Answer 1

Here is a start for the first one, hopefully this helps or gets you started. \[H _{2}SO _{4} (aq)\rightarrow 2 H ^{+} (aq) + SO _{4}^{2-} (aq) \]
\[Ba(OH)_{2} (S) \rightarrow Ba ^{2+}(aq) +2 OH ^{-}\]

Check out this link http://faculty.icc.edu/bcook/ch4.pdf
it has some good information and shows you the different equations and how to complete them.

Answer 2

I am not very good at balancing equtions

Answer 3

it's a double displacement reaction. swap the reactant partners to form the products

Answer 4

To get through chemistry, especially general you're are going to have to practice balancing equations. Practicing is the best way to learn! However, if you are really stuck here is a great guide that walks you through step by step through balancing all the different types of reactions from single to double displacement. http://schs.stvrain.k12.co.us/registration/summerassign.schedule%20changes/AP%20Chemistry/Writing,%20Balancing%20and%20Predicting%20Products%20of%20Chemical.pdf

If you are still lost after this its best to ask your instructor for some extra help, or check out some youtube videos and see if they help. Best of luck!

Answer 5

One quick thing if you want an actual instructor to walk you through and explain everything step by step. There is an absolutely free online tutoring site http://www.pathwhelp.org and they have different instructors with specialties in everything from chem to english and they'll explain everything to you in no time.

Answer 6

is it H2S04 + BA(OH)2 ARROW TO H2(OH)2+BAS04

Answer 7

because each H has a charge of +1, and each OH has a charge of -1, you'll form 2 molecules of H-OH, or H2O, water

Answer 8

it is mostly balanced, just change the formula from H2(OH)2 into 2H2O, and it's done

Answer 9

H2S04 + BA(OH)2 ARROW TO 2H20+BAS04

RIGHT

Answer 10

it's balanced, now what about the phases?

Answer 11

H2S04 (aq) + BA(OH)2 (aq) ARROW TO 2H20(l)+BAS04(aq)

Answer 12

right

Answer 13

the \(BaSO_4\) is an insoluble precipitate, so it's phase is (s)

Answer 14

and the next one would be

HC2H3O2 (aq) + NH3 (aq) <--> NH4+ (aq) + C2H3O2-(aq)

Answer 15

I pretty much suck in chemistry but I believe you have balanced that equation correctly.

Answer 16

well anyone else knows

Answer 17

the first one is this H2S04 (aq) + BA(OH)2 (aq) ARROW TO 2H20(l)+BAS04(s)

the second one is this HC2H3O2 (aq) + NH3 (aq) <--> NH4+ (aq) + C2H3O2-(aq)

Answer 18

am i correct

Answer 19

Yes, both are correct.

Answer 20

2nd part is to identify the conductivities

Answer 21

in the chemical reactions

Answer 22

can you help me with that

Answer 23

conductivity depends on the presence of free ions in a solution. Once the products of each reaction have been formed, which one has loose ions, and would therefore conduct electricity?