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Ok so we have a reaction 4 KO2 + 2 CO2 ---> 2 K2CO3 + 3 O2 .425mol KO2 and .319 mol O2 and the question is How many grams of KO2 are needed to form 8.0 g of O2
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@Preetha
@JFraser @msamman10
\(KO_2\) isn't a proper formula, it should be \(K_2O\). Start with the mass of O2 needed, then convert that into moles, then use the mole ratio from the balanced equation to find the moles of \(K_2O\) needed to produce that amount
the question says KO2
potassium superoxide does exist. but I am not sure it's applications.
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i forgot about superoxides, but the process is exactly the same
Ok thanks
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