Question

5. Calculate the concentration of K+ and MnO4- in ppm for your two solutions?

Answer 1

250 mL of 2.5 × 〖10〗^(-3)M KMnO4 solution
Prepare 50 mL of a 5 ×〖10〗^(-4)M solution from the previous solution
7. Prepare a 1:10 dilution from the previous solution.

Answer 2

ppm = mg/L
you have the concentration in moles per liter, for each mole of KMnO4 you have one mole of K+ and one mole of MnO4-.
You have to multiply the concentration (2.5 x 10^-3) by the molecular mass (MM) of the K+ (39.098g/mol) or by the MM of the MnO4- (118.936 g/mol) to get the g/L of the respective ion in solution.
Then multiply by 10^3 to convert g/L -> mg/L that is going to be equal to ppm.

To prepare the dilution you can use the V1 x C1 =V2 x C2 formula

Answer 3

I've already prepared the solution I just wasn't sure how to get the k+ or MnO4