Question

Find the vertex for the quadratic function.
u(x)= 0.5x^2-2x+5

Answer 1

@ganeshie8

Answer 2

first coordinate is \(-\frac{b}{2a}\)

Answer 3

1? i dont get how to set it up

Answer 4

as you have

u(x)= 0.5x^2-2x+5

here a = 0.5, b = -2 and c = 5

to find the first coordinate of vertex we have

x = -b/(2a)

find x and put it in

u(x)= 0.5x^2-2x+5 to find u(x) = y

thus you will get both coordinates

(x,y) =(........,.........)

Answer 5

no no i mean how to put it in vertex "form"

Answer 6

dont u first subtract 5 so it would be:

Answer 7

@Ammarah
To find VERTEX,we have its co=ordinates as :-
\[\large \bf Vertex(\frac{-b}{2a},\frac{-D}{4a})\]

Answer 8

a(x-b/2a)^2 + k =

Answer 9

first write in standard form(ax^2+by+c=0) and then use that formula

Answer 10

it is in tat form/!!!

Answer 11

correct and then use that formula

Answer 12

yes my question is how to write the vertex form all u guys r doing is teling me which formula to use@

Answer 13

\(-\frac{b}{2a}=2\) if i am not mistaken

Answer 14

is that correct?

Answer 15

@Ammarah use that formula(in attachment)

Answer 16

i wouldn't

Answer 17

you are correct.. -b/2a=2

Answer 18

we get \[-\frac{b}{2a}=2,u(2)=3\] so the vertex is \((2,3)\) and therefore the vertex form is
\[.5(x-2)^2+3\]halas

Answer 19

umm -2/2^2 is 3?

Answer 20

i must have lost you

\[-\frac{b}{2a}=-\frac{-2}{2\times .5}=\frac{2}{1}=2\]

Answer 21

@satellite73 he want to find the co-ordinates of VERTEX

Answer 22

not its form

Answer 23

\[.5x^2-2x+5\]
\[ax^2+bx+c\]
\[a=.5,b=-2,c=5\]

Answer 24

ok please show step by step

Answer 25

\[-\frac{b}{2a}=...=2\]and
\[.5\times 2^2-2\times 2+5=3\]

Answer 26

u lost

Answer 27

u lost me at the times part

Answer 28

@Ammarah my solution is correct and appropriate

Answer 29

your question wants to say that you have to find the vertex(its co-ordinates)

Answer 30

−b2a=2,u(2)=3
so the vertex is (2,3) and therefore the vertex form is
.5(x−2)2+3

I dont get how you just skipped to the .5 (x-2) part please show how u got there

Answer 31

first ,find its x-coordinate

Answer 32

just show me............i will uderstand if u just show me the steps

Answer 33

Vertex's x coordinate=-b/2a

where b=-2 and a=0.5

after simplify,we get
\[\large \bf \frac{-b}{2a}=-\frac{-2}{0.5}=2\]

Answer 34

understood till here ?