If 0.4506 g of KHP standard were titrated with NaOH and the endpoint was reached at 27.96 mL, what is the concentration (molarity) of the NaOH solution?

Question

nincompoop · Answer

let me see you solve it first

kkutie7 · Answer

I can't that's the problem... I'm not sure where to start.

nincompoop · Answer

what is titration?
what is endpoint?

nincompoop · Answer

you must know something to begin with

cuanchi · Answer

KHP, stand for potassium hydrogen phthalate with a MM 204.22 g/mol and react one mole to one mole with NaOH (~40g/mol)

nincompoop · Answer

what is equilibrium?
something to begin with

kkutie7 · Answer

$$.4506g KHP*\frac{ 1mole KHP }{ 71.0799g KHP }*\frac{ 1moleNaOH }{ 1 mole KHP }*$$
$$\frac{1}{.02796L}$$
does this look even a bit right?

kkutie7 · Answer

I figure endpoint should mean 1:1 moler ratio

cuanchi · Answer

The MM of the KHP is NOT 71.0799 g/mol, it is 204.22 g/mol (C8H5KO4)

kkutie7 · Answer

my mistake.... but how about the rest of my problem?

cuanchi · Answer

http://en.wikipedia.org/wiki/Potassium_hydrogen_phthalate the rest is fine

nincompoop · Answer

first write the balanced chemical equation

nincompoop · Answer

it is asking for molarity so your dimensional analysis must be able to indicate molarity (solute per liter)
$$M = \frac{moles_{solute}}{Liters_{solution}}$$

kkutie7 · Answer

was what I did wrong?

kkutie7 · Answer

$$C_8H_5KO_4+NaOH \rightarrow KNaC_8H_4O_4 +h_2O$$
is this good enough?

kkutie7 · Answer

$$.4506g KHP*\frac{ 1mole KHP }{ 71.0799g KHP }*\frac{ 1moleNaOH }{ 1 mole KHP }*$$
$$\frac{1}{.02796L}$$
whats wrong with is?

kkutie7 · Answer

*this

nincompoop · Answer

submit it and see

kkutie7 · Answer

=/ I'm not working with sapling or something like that. I can't just submit it for a  check.

nincompoop · Answer

that is how it is during exam 
you don't get to ask your professor if it is correct before you submit

nincompoop · Answer

why aren't you confident with your solution is the question

cuanchi · Answer

Change the molecular mass from 71 to 204 !!!

nincompoop · Answer

LAUGHING OUT LOUD I thought you corrected that one already @Cuanchi

nincompoop · Answer

this is why I asked to write the balanced chemical equation

nincompoop · Answer

did you use the masses of  
potassium, hydrogen and phosphorus?

cuanchi · Answer

Many students commit this mistake

nincompoop · Answer

your analysis is correct by the way 
I was adamant about the balanced equation so you can spot where the mistake was