Question

Solve:
1 11 years ago

Answer 1

Let's break it up into 2 inequalities:
\(x^2<4\) and \(x^2>1\)
Recall that \(\sqrt{x^2}=|x|\)

\(x^2<4 \implies |x|<2\)

and
\(x^2>1\implies |x|>1\)

Answer 2

@kirbykirby I saw you type something, why didn't it pop up??

Answer 3

My open study is lagging a bit. oye

Answer 4

This is my logic
for the left part, we have 1<x^2 --> -1<x<1
for the right part , we have -2<x<2
so that intersection between them is