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integrate 1/t(t^2-1)^1/2
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A long way would be to allow \(u=t^2-1\). This is awfully ugly and required integration by parts. Though, I'm sure there is a nicer way.
ok
cn u solve it completely
I mean, it can be solved completely, but I'm not going to write it all up. Here's the gist: \[ \int_\gamma \frac{dt}{t\sqrt{t^2-1}}=\int_\gamma \frac{du}{(u-1)\sqrt{u}} \]Do integration by parts on the last integral and you should get the answer.
That should be a \(u+1\), not \(u-1\).
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Made a mistake, the integral is this: \[ \int_\gamma \frac{dt}{t\sqrt{t^2-1}}=\frac{1}{2}\int_\gamma \frac{du}{(u+1)\sqrt{u}} \]
ok i got it thanks
Easier method: Let \(u=\sqrt{t^2-1}\)!
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