Radicals with odd index roots (3, 5, 7, etc.) can have: Select one: a. Positive answers only b. Negative answers only c. Both positive and negative answers d. Only odd root answers
@rational
@XVasHappeninZen @myininaya @DangerousJesse
let me see...
With cube and other odd roots, you can take them of negative numbers. For example the cube root of 8 is 2 since 2^3 = 2*2*2 = 8. What if it's the cube root of -8? Note that (-2)^3 = (-2)*(-2)*(-2) = -8. When you multiply an odd number of negatives, the answer is negative. That's why you can take odd roots of negative numbers. Does this answer your question or do you know this?
so the answer would be B negative answers only?
@XVasHappeninZen
i think yes
@iGreen
@DangerousJesse @iambatman
@igreen help
should i just go with B
Sorry, I was dealing with something. One sec.
no just look at the question
I'd say C, actually. Because \(^3\sqrt{x}\) and \(^3\sqrt{-x}\) can have odd and even answers, I don't see how -2\(^3\) was relevant, but okay.
@prowrestler
\[\sqrt[3]{x^{3}}- 3x^{2}+1=x\]
This one is going to take too long to type out using Mathjax, so here.
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