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Mathematics 21 Online
OpenStudy (happyfeet8040):

The graph of f(x) = (0.5)x is replaced by the graph of g(x) = (0.5)x - k. If g(x) is obtained by shifting f(x) down by 5 units, the value of k is ________. @FibonacciChick666

OpenStudy (fibonaccichick666):

so, graph it to start

OpenStudy (happyfeet8040):

Okay, how would I graph it?

OpenStudy (fibonaccichick666):

f(x)=y, then just pick some convenient x values

OpenStudy (happyfeet8040):

So, f(x) = (0.5)x?

OpenStudy (happyfeet8040):

wait..

OpenStudy (fibonaccichick666):

yea

OpenStudy (happyfeet8040):

Okay.

OpenStudy (fibonaccichick666):

now, what is the y intercept?

OpenStudy (happyfeet8040):

g(x)?

OpenStudy (fibonaccichick666):

no, did you graph f(x)?

OpenStudy (happyfeet8040):

Yes.

OpenStudy (fibonaccichick666):

at what x value does y=0?

OpenStudy (happyfeet8040):

Well, a y-intercept is a point in the equation where the x-value is zero.

OpenStudy (happyfeet8040):

I'm sorry, I'm really confused.

OpenStudy (happyfeet8040):

y = 0 when x does?

OpenStudy (fibonaccichick666):

yea it's both intercepts in one sorry x and y, so I used interchangable words, now if you move it down 5 units, what is the y-intercept?

OpenStudy (happyfeet8040):

-7?

OpenStudy (fibonaccichick666):

? what was the original y intercept?

OpenStudy (fibonaccichick666):

y=0 x=0 correct?

OpenStudy (happyfeet8040):

Ohhh okay, so 5?

OpenStudy (happyfeet8040):

@FibonacciChick666

OpenStudy (fibonaccichick666):

+ or -

OpenStudy (fibonaccichick666):

then what is the standard eq of a line? then plug and chug :)

OpenStudy (happyfeet8040):

negative?

OpenStudy (fibonaccichick666):

yea, so now what is the standard eq of a line?

OpenStudy (happyfeet8040):

I honestly have no clue.. lol im sorry.

OpenStudy (fibonaccichick666):

ok, just google it then

OpenStudy (happyfeet8040):

okay, and -5 is the answer?

OpenStudy (fibonaccichick666):

or use purplemath it's better

OpenStudy (fibonaccichick666):

and no, not yet

OpenStudy (fibonaccichick666):

you need to look at the standard and compare it to your given to determine k

OpenStudy (happyfeet8040):

okay, thanks! :)

OpenStudy (fibonaccichick666):

np, what did you get?

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