Question

we have x² + 2x + 2 = 0

Using the quadratic formula we get:

x = [-2 ± √(2² - 4(1)(2))]/2

i.e. [-2 ± √-4]/2

Now, we have to break up the √-4 in to something more managable

so, √-4 = √4√-1

and as √-1 = i...an imaginary root of -1 we have:

√4√-1 => 2i

Therefore, we have [2 ± 2i]/2

This simplifies to 1 ± i